-1.2x^2+48x=300

Solution for -1.2x^2+48x=300 equation:

-1.2x^2+48x=300

We move all terms to the left:

-1.2x^2+48x-(300)=0

a = -1.2; b = 48; c = -300;
Δ = b2-4ac
Δ = 482-4·(-1.2)·(-300)
Δ = 864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-12\sqrt{6}}{2*-1.2}=\frac{-48-12\sqrt{6}}{-2.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+12\sqrt{6}}{2*-1.2}=\frac{-48+12\sqrt{6}}{-2.4}
$